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Dual spaceIn mathematics the existence of a 'dual' vector space reflects in an abstract way the relationship between row vectors (1xn) and column vectors (nx1). The construction can also take place for infinite dimensional spaces and gives rise to important ways of looking at measures, distributions and Hilbert space. The use of the dual space in some fashion is thus characteristic of functional analysis. It is also inherent in the Fourier transform.
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Given any vector space V over some field F, we define the dual space V* to be the set of all linear functions from V to F. These linear functions to the base field are also called linear functionals. V* itself becomes a vector space over F under the following definition of addition and scalar multiplication:
If the dimension of V is finite, then V* has the same dimension as V; if {e1,...,en} is a basis for V, then the associated dual basis {e1,...,en} of V* is given by
Concretely, if we intepret Rn as space of columns of n real numbers, its dual space is typically written as the space of rows of n real numbers. Such a row acts on Rn as a linear functional by ordinary matrix multiplication.
If V consists of the space of geometrical vectors (arrows) in the plane, then the elements of the dual V* can be intuitively represented as collections of parallel lines. Such a collection of lines can be applied to a vector to yield a number in the following way: one counts how many of the lines the vector crosses.
If V is infinite-dimensional, then the above construction of ei doesn't produce a basis for V* and the dimension of V* is greater than that of V. Consider for instance the space R(ω), whose elements are those sequences of real numbers which have only finitely many non-zero entries. The dual of this space is Rω, the space of all sequences of real numbers. Such a sequence (an) is applied to an element (xn) of R(ω) to give the number ∑nanxn.
As we saw above, if V is finite-dimensional, then V is isomorphic to V*, but the isomorphism isn't natural and depends on the basis of V we started out with. In fact, any isomorphism Φ from V to V* defines a unique non-degenerate bilinear product[?] on V by
and conversely every such non-degenerate bilinear product on a finite-dimensional space gives rise to an isomorphism from V to V*.
There is a natural homomorphism Ψ from V into the double dual V**, defined by (Ψ(v))(φ) = φ(v) for all v in V, φ in V*. This map Ψ is always injective; it is an isomorphism if and only if V is finite dimensional[?].
When dealing with a normed vector space V (e.g., a Banach space or a Hilbert space), one typically is only interested in the continuous linear functionals from the space into the base field. These form a normed vector space, called the continuous dual of V, sometimes just called the dual of V. It is denoted by V '. The norm ||φ|| of a continuous linear functional on V is defined by
One may also talk about the continuous dual of an arbitrary topological vector space. This is however much harder to deal with since it will in general not be a normed vector space in any natural way.
For any finite-dimensional normed vector space or topological vector space, such as Euclidean n-space, the continuous dual and the algebraic dual coincide.
Let 1 < p < ∞ be a real number and consider the Banach space l p of all sequences space of sequences a = (an) for which
In a similar manner, the continuous dual of l 1 is naturally identified with l ∞. Furthermore, the continuous duals of the Banach spaces c (consisting of all convergent sequences, with the supremums norm) and c0 (the sequences converging to zero) are both naturally identified with l 1.
If V is a Hilbert space, then its continuous dual is a Hilbert space which is anti-isomorphic to V. This is the content of the Riesz representation theorem, and gives rise to the bra-ket notation used by physicists in the mathematical formulation of quantum mechanics.
In analogy with the case of the algebraic double dual, there is always a naturally defined injective continuous linear operator Ψ : V → V '' from V into its continuous double dual V ''. This map is in fact an isometry, meaning ||Ψ(x)|| = ||x|| for all x in V. Spaces for which the map Ψ is a bijection are called reflexive.
The continuous dual can be used to define a new topology on V, called the weak topology.
perhaps advise you on many points, and recommend you to his friends."
"Your mother is right," said Antinous. "Claudius Venator can be very
speaking, for he felt himself strongly attracted by Hadrian's imposing
desirable to revel with him for a while.
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amusing disguise and procure masks for him and for me and, if you like,
other disguise."
"go/good.html">Good," replied the sculptor. "I will go at once and order what is
in our workshop and in half an hour I will be back with the things."
"But pray make haste," Antinous begged him. "My master cannot bear to be
to the artist.html">artist.html">artist. He laid his hand on his shoulder and said in a low voice
him that is not in Hadrian's favor."
"Is your master Caesar's spy?" asked Pollux, looking suspiciously at
is the case--"
"No, no," interrupted the lad hastily.
"Anything but that; but the two have no secrets from each other and
artist with an expression of warm regard on his handsome features and
dame Doris, whose old eyes had been fixed as if spellbound on Antinous,
out:
"Oh! what a splendid creature! moulded by the gods.html">gods! sacred to the gods!
earth."
"Look at my old woman.html">woman!" exclaimed Pollux laughing, "but in truth friend,
take his likeness you can show the world.html">world a thing worth seeing."
"Will you?" interrupted Pollux turning to Hadrian's favorite.
"I have never yet been able to keep still for any artist," said Antinous.
you too should join in the chorus with the rest of the world. Farewell
but as to what is beautiful that I know as well as any other woman in
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